What is the formula for finding centripital acceleration in a spinning disc?

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The discussion focuses on calculating the centripetal acceleration of two objects on a spinning disc, with Object A at a distance R from the center and Object B at R/2. The velocities for both objects are given as VB=piR/T and VA=2piR/T. The correct formula for centripetal acceleration is identified as a = v²/R, leading to the conclusion that the acceleration for Object B is a = (2pi²R)/T². The confusion arose from incorrectly using R instead of R/2 in the calculations, which was resolved after further review. Ultimately, the correct centripetal acceleration formula was clarified.
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Homework Statement


There is a spinning disc. Object A sits R distance from center and object B sits R/2 distance away. VB=piR/T and VA=2piR/T


Homework Equations


Find the magnitude of the acceleration of object B. Assume that the cylinder makes one complete turn in a period of time .



The Attempt at a Solution


The answer is a=(2pi2R)/T2 .


From using centripital acceleration=v2/R , i got
ac=pi2R/T2

There is a coefficient of 2 that I am missing in my answer from the correct solution, but I have double checked. Am I using the wrong formula here? where did the 2 come from in the answer?
 
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NVM. spent an hour on it and finally got it. Supposed to divide by R/2 not R
 

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