What is the formula for the electric field above a plane?

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The discussion focuses on deriving the electric field above a uniformly charged wire of length L, with a specific point P at a perpendicular distance x from the midpoint. The correct formula for the electric field is given as E = (lambda/2*pi*epsilon_0) * (L/x*sqrt(L^2+4x^2). Participants are troubleshooting integration steps and substitutions, particularly regarding the use of cos(theta) and variable changes to simplify the integral. One participant notes that using a different variable for integration leads to the correct result, while others express confusion over their integration methods. Ultimately, the conversation revolves around finding a consistent approach to arrive at the correct electric field expression.
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Homework Statement


This is problem 47(chapter 21) in the textbook - Physics for engineers and scientists (Giancoli)
Uniformly charged wire has length L, where point 0 is the mid point. Show that the field at P, perpendicular distance x from 0 is

E= (lambda/2*pi*epsilon_0) *(L/x*sqrt(L^2+4x^2)

Homework Equations

The Attempt at a Solution



I tried solving it, I got E = - (lambda/2pi*epsilon_0)*[1/sqrt(L^2+4x^2)-1/2x)
Is something wrong with my integration?

My attempt is correct until

E= lamda/r^2*4pi*epsilon_0 * integration (cos theta)dl

After this, I use cos theta = x/r (r is the hypotenuse = sqrt (L^2+4x^2))

I am trying to do this instead of taking r=x cos theta.
 
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Looks like something wrong with the "(cos theta)dl."
I'll use A instead of theta. And z in place of your l, running from -L/2 to L/2.
I get some constants times integral of cos(A)/(x^2 + z^2)*dz
Since tan(A) = z/x, I can use z = x*tan(A) to simplify the integral.
And dz = x*sec^2(A) dA
After the dust settles on this change of variable, I get integral of cos(A)dA.

Not the difference from your integral: I have dA where you have dl
I end up with the given answer.
 
If I use r=cos theta/x, then i get the correct result.
I am trying to get there without that substitution and just cos theta = x/sqrt(x^2+(l/2)^2)
huh. Doesn't work if I use the integral but does work if I take l/2 as y initially. The whole term becomes (x^2+y^2) and then apply limit to get answer.
 
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