What is the frequency of a photon of energy 58eV?

AI Thread Summary
To find the frequency of a photon with energy of 58 eV, the equation E = hF is used, where E is energy, h is Planck's constant (6.63 x 10^-34 J·s), and F is frequency. The energy must be converted from electronvolts to joules, using the conversion factor 1 eV = 1.602 x 10^-19 J. After conversion, the frequency can be calculated correctly by rearranging the formula to F = E/h. The discussion emphasizes the importance of using consistent units, specifically MKS (meters, seconds, kilograms), for accurate calculations.
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Homework Statement



What is the frequency of a photon of energy 58eV?

Homework Equations



E=hF

where H is Planck's constant, 6.63x10^-34



The Attempt at a Solution



58/ (6.63x10^-34) = 8.75e34

that is not correct.

Do i have the energy eV into a certain unit?
 
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Hint: 1eV = 1.602E-19 J
 
When in doubt, put everything in units of MKS (meters, seconds, and kg).

MKS energy unit is the Joule = kg * m^2 / s^2
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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