Calculating Frequency and Distance of a Sound Wave

AI Thread Summary
The discussion focuses on calculating the frequency, number of complete waves emitted, and the distance traveled by a sound wave with a wavelength of 0.70 m and a velocity of 330 m/s over 0.50 seconds. The frequency is correctly calculated as 471.4 Hz using the formula f = V/λ. For the number of complete waves emitted, participants clarify that it can be found by multiplying the frequency by the time, resulting in 235 waves. The distance traveled by the wave front is confirmed to be 165 m, calculated as the product of time and wave velocity. Overall, the calculations and understanding of the concepts are validated through collaborative discussion.
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A sound wave of wavelength 0.70 m and velocity 330 m/sec is produced for .50 s.

A) What is the frequency of the wave?
B) how many complete waves are emitted in this time interval?
c) after .50 s, how far is the front of the wave from the source of the sound?

AnsA) V= (Lambda)(f)
f= V/Lambda = 330/.70= 471.4 Hz

Ans b) I don't know how to do this.. is this the frequency?

Ans c) Lambda = (.50) ( 330) = 165 m

Are the above answers correct? also, i'd appreciate it if you guys could help me for the second question ( part b )

thanks
 
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jai6638 said:
A sound wave of wavelength 0.70 m and velocity 330 m/sec is produced for .50 s.

A) What is the frequency of the wave?
B) how many complete waves are emitted in this time interval?
c) after .50 s, how far is the front of the wave from the source of the sound?

AnsA) V= (Lambda)(f)
f= V/Lambda = 330/.70= 471.4 Hz

Ans b) I don't know how to do this.. is this the frequency?

Ans c) Lambda = (.50) ( 330) = 165 m

Are the above answers correct? also, i'd appreciate it if you guys could help me for the second question ( part b )

thanks
Seems correct, for question B think of it like this. If you emit the wave for a time so that it passes 1.4m how many complete waves will you have emitted?
Then if you emit for a time so that it passes 1.5m? And if it passes lambda*v?
 
(330) ( .50) = 165 m ...

165/ .70 = 235 waves?

damn. that doesn't sound right..
 
jai6638 said:
AnsA) V= (Lambda)(f)
f= V/Lambda = 330/.70= 471.4 Hz

Ans b) I don't know how to do this.. is this the frequency?
Think of it this way. The frequency (which you found in part a) is the number of cycles (or waves) produced each second. So... the number of waves produced in a given time must equal f \times t.
 
471.4 waves produced each second.

therefore, in half second = 471.4 * .5 ( f x t) = 235 waves?

i still get the same answer... doh..
 
You'd better get the same answer!
 
oh ok .. lol.. i thought the answer was wrong.. alright thanks a lot...finally understood it :)
 
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