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Homework Help: What is the magnitude of the magnetic field inside the toroid

  1. Nov 15, 2005 #1
    A toroid having a square cross section, 5.00 cm on a side, and an inner radius of 16.0 cm has 600 turns and carries a current of 0.700 A. (It is made up of a square solenoid bent into a doughnut shape.)

    (a) What is the magnitude of the magnetic field inside the toroid at the inner radius?
    5.25e-4 T
    (b) What is the magnitude of the magnetic field inside the toroid at the outer radius?
    ? T


    I keep missing part B. I tried:
    B = PERMIVITY*n*I
    where n = N/(2PI*R);
    N is the number of turns:
    R is the radius of the toroid. PERMITIVITY = 4PIE-7;
    So i plugged in
    n = 600/(2PI*.05)
    B = 4PIE-7*.700*n which was wrong! any ideas?
     
  2. jcsd
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