A toroid having a square cross section, 5.00 cm on a side, and an inner radius of 16.0 cm has 600 turns and carries a current of 0.700 A. (It is made up of a square solenoid bent into a doughnut shape.)(adsbygoogle = window.adsbygoogle || []).push({});

(a) What is the magnitude of the magnetic field inside the toroid at the inner radius?

5.25e-4 T

(b) What is the magnitude of the magnetic field inside the toroid at the outer radius?

? T

I keep missing part B. I tried:

B = PERMIVITY*n*I

where n = N/(2PI*R);

N is the number of turns:

R is the radius of the toroid. PERMITIVITY = 4PIE-7;

So i plugged in

n = 600/(2PI*.05)

B = 4PIE-7*.700*n which was wrong! any ideas?

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# Homework Help: What is the magnitude of the magnetic field inside the toroid

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