What is the mass of water used to cool the iron car engine?

AI Thread Summary
The discussion revolves around calculating the mass of water used to cool a 250 kg iron car engine, which initially has a temperature of 35°C and cools to an air temperature of 10°C. The total heat released during this cooling process is 4.4 x 10^6 J. The user applied the formula for heat transfer for both iron and water, ultimately determining that the mass of water required for cooling is 15.0 kg. The calculations were confirmed as correct by other participants in the thread. This highlights the importance of applying relevant formulas and showing work in problem-solving.
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A 2.50 x 10^2 kg iron car engine contains water as coolant. Suppose the temperature of engine is 35 degree celcius when it shut off and air temperature is 10degree celcius. The heat given off by engine and watering it as they cool to air temperature is 4.4 x10^6 J. What is the mass of water used to cool engine?
 
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You must make an attempt at solving the problem before help can offered. What formulas are relevant? What have you tried?
 
gneill said:
You must make an attempt at solving the problem before help can offered. What formulas are relevant? What have you tried?

This is what i did:

Q for iron = mc(tf-ti)
= 2.50 x 10^2 kg x 450 J/kg/°c x (10°c - 35°c)
= -2.813 x 10^6 J

Q for water = 4.4 x10^6 J - 2.813 x 10^6 J
= 1.587 x10^6 J

mass for water = Q / c x (tf-ti)
= 1.587 x10^6 J / 4180 x ( 10°c - 35°c)
= 15.0 kg

Is it right?
 
That looks fine.
 
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