What is the momentum of a proton moving at 0.7c?

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The momentum of a proton with a rest mass of 1.67 x 10^-27 kg moving at 0.7c is calculated using relativistic equations. The energy is first determined as E = 2.10 x 10^-10 J. Using the equation E^2 = (pc)^2 + (mc^2)^2, the momentum is found to be p = 8.47 x 10^-15 kg*m/s. However, another participant reports a different result of 4.88 x 10^-19 kg*m/s, suggesting a possible arithmetic error in the calculations. The discussion emphasizes the importance of detailed calculations to resolve discrepancies in results.
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Homework Statement



A proton of rest mass 1.67 x 10^-27 kg is moving at a constant speed of 0.7c

What is it's momentum?

Homework Equations


The Attempt at a Solution



Using E = γmc^2 I obtained;

E = 2.10 x 10^-10 JThen with;

E^2 = (pc)^2 + (mc^2)^2 and solving for p I got;

p = 8.47 x 10^-15
 
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ZedCar said:

Homework Statement



A proton of rest mass 1.67 x 10^-27 kg is moving at a constant speed of 0.7c

What is it's momentum?


Homework Equations





The Attempt at a Solution



Using E = γmc^2 I obtained;

E = 2.10 x 10^-10 J
I agree.

Then with;

E^2 = (pc)^2 + (mc^2)^2 and solving for p I got;

p = 8.47 x 10^-15
That's the correct method, but I'm getting something quite different. It is probably just an arithmetic mistake. Can you show more details of this calculation?
 
Redbelly98 said:
I agree.That's the correct method, but I'm getting something quite different.

Are you getting 4.88 x 10^-19 ?
 
Yes, with units of kg*m/s.
 
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