What is the Net Force Acting on a Truck and Trailer System?

AI Thread Summary
The discussion revolves around calculating the net force acting on a truck and trailer system, where a 1200 kg truck tows a 300 kg trailer. The user attempts to apply Newton's second law (F=ma) but struggles with the correct setup, particularly in determining acceleration due to a lack of clear information about the trailer's movement. They calculate forces based on the weights of the truck and trailer but realize their approach is incorrect after receiving feedback from an online homework platform. Clarification is needed regarding the trailer's distance traveled and the time taken to accurately compute acceleration and net force. The conversation emphasizes the importance of understanding the problem context to apply physics principles correctly.
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Homework Statement



A 1200 kg pickup truck tows a small 300 kg trailer using a relatively lightweight tow rope. The position of the trailer is given in m and time in s. *There is an animation which shows the truck pulling the trailer across X-axis.
Given: x= -20; y= +1 **BTW, i don't know what the given has to do with anything here! :x
Starts from zero ends at 16 seconds.

Homework Equations



I know F= ma. They did not give acceleration so I looked up my notes and found that:
if I set p=truck and r= trailer g=ground, then

a = Fpg - Frg/ (mp + mr) ... a= F/m


The Attempt at a Solution



but I'm not sure if I set that up right! I mean i took mass of truck (p) = 1200kg x 9.8 m/s^2 to give me 11760 N then mass of trailer (r) = 300 kg x 9.8 m/s^2 to give me 2940 N. (11760-2940/(1200+300) = 8820/1500 = a = 5.88.
So if F= ma, then F = 1500 x 5.88 which gives me 8820 N.

Is this correct? What should I do? Please help...physics scares me lol

OK, so i know its incorrect bc I got it wrong on my online homework (webassign). So...?
 
Last edited:
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You are going to have to clarify the problem. Does the truck-trailer system travel 20 meters in 16 seconds? You'd have to calculate the acceleration, then the net force providng that acceleration. Welcome to PF.
 
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