What is the Net Force on an Angled Surface in a Limited Force Scenario?

AI Thread Summary
The discussion centers on the net force acting on a part subjected to pressure on all surfaces, specifically focusing on an angled surface. The original poster questions whether the force acting against the 45-degree angle should be considered as X in the parallel direction or as cos(45)*X. An engineer suggested that the force is X parallel to the centerline, which the poster finds confusing. Clarifications indicate that if pressure acts on all surfaces, the net force would be zero, implying equilibrium, while pressure on external surfaces would require calculating the net force based on the projected area. The conversation emphasizes the importance of understanding how pressure affects force distribution on angled surfaces.
rush02112
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I prepared a drawing to reference what i am trying to explain:

http://i20.photobucket.com/albums/b225/rush02112/part1.jpg

I will have pressure acting against the all surfaces of this part. Notice this part will only be able to move parallel to the center line of the part. I want to know if the net force acting against the 45 degree angle will be X in parallel direction of the centerline or if it is [cos(45)*X]

I was told by the engineer i work with that the angled surface will be pushed with force X parallel to the centerline. This is why i ask since that doesn't make sense to me. I would think that the force would act on the angled surface perpendicular to which the resulting force would be [(cos(45)*x]
 
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rush02112 said:
I prepared a drawing to reference what i am trying to explain:

http://i20.photobucket.com/albums/b225/rush02112/part1.jpg

I will have pressure acting against the all surfaces of this part. Notice this part will only be able to move parallel to the center line of the part. I want to know if the net force acting against the 45 degree angle will be X in parallel direction of the centerline or if it is [cos(45)*X]

I was told by the engineer i work with that the angled surface will be pushed with force X parallel to the centerline. This is why i ask since that doesn't make sense to me. I would think that the force would act on the angled surface perpendicular to which the resulting force would be [(cos(45)*x]

If you really mean that you have a pressure acting on all of the surfaces, internal and external, then the net force will be zero and the part will be in equilibrium.

If you mean that you have pressure acting on the external surface only, then the net force is given by the "frontal area" or "projected area" multiplied by the pressure. This area is the area you see if you look at the part from the end.
 
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Im just concerned about the 1 external angled surface at the moment. When this part is assembled in the tool, only a limited number of surfaces will see the force described. I wanted to try and keep the drawing and description as simple as possible
 

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