What is the Net Ionic Equation for Nickel Nitrate and Lithium Sulfide?

AI Thread Summary
The discussion centers on determining the net ionic equation for the reaction between nickel nitrate and lithium sulfide. Participants note that nickel nitrate is likely nickel (II) nitrate due to the solubility of nitrates. It is clarified that no oxidation occurs in this reaction, indicating it is not a redox reaction. The focus shifts to identifying the actual reaction that takes place between the two compounds. Ultimately, the conversation emphasizes the importance of understanding the nature of the reactants and the type of reaction involved.
ccmetz2020
Messages
15
Reaction score
0


1. A solution of nickel nitrate is added to a solution of lithium sulfide. (you MUST write as a Net Ionic if appropriate).
a. BALANCED EQUATION
b. Which substance is being oxidized?

2. none really

3. I don't really have much of an attempt because it doesn't specify in the question whether I'm dealing with nickel (ii) nitrate or nickel (iii) nitrate. I know that nitrate is soluble so the answer will be a net ionic equation, but the balanced equation is hard for me to figure out. Could anyone help me here?
 
Physics news on Phys.org
I bet they mean Ni(II).

What do you know about sulfides?

--
methods
 
Nevermind. It was a trick question, nothing is being oxidized. It isn't a redox reaction!
 
That was obvious :smile:

Question is - do you know what reaction DOES take place?

--
 
Last edited:
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top