What Is the Normal Stress in a Prismatic Bar Under Tension?

AI Thread Summary
To find the normal stress in a prismatic bar under tension, the formula used is stress equals force divided by area. In this case, a force of 100 N is applied to a bar with a cross-sectional area of 5 cm². The correct calculation involves converting the area to m², resulting in a stress of 20,000 Pa or 20 kPa. Confusion arose regarding unit conversions and whether the force should be doubled if the bar is supported in the middle. Clarification on the derived units of Pascal confirms they are indeed N/m².
Baumer8993
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Homework Statement


In a prismatic bar (same cross sectional area throughout the entire length), the load applied to both ends is 100 N causing the member to be in tension. If the cross sectional area of the member is
5 cm2. What is the normal stress in the in kPa?


Homework Equations


stress = force / area


The Attempt at a Solution



I first tried without looking at the units, and got 20, which is wrong. I next tried converting everything to m2 to get the answer is pascals the convert to kPa. I got 200 for my second answer. What am I doing wrong? This seems like such a simple problem!
 
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What are the derived units of a Pascal? Are they N/m^2 or N/cm^2?
 
They are N/m^2. I used an online converter to check, so I confused about what I did wrong.
 
Is the bar supported in the middle? If so, should the force be 100 or 200 N?
How did you get 20?
 
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