What is the Peak Current When Discharging Static Electricity?

AI Thread Summary
When a person discharges static electricity after shuffling on a carpet, their body acts as a 100-pF capacitor charged to 20,000 V. Upon touching a grounded object, the discharge occurs through a resistance of 100Ω. The time constant for the discharge is calculated to be 0.01 μS. The peak current during this discharge can be estimated at 200 A. Understanding these values helps clarify the nature of static electricity shocks.
Ryantruran
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Homework Statement



When a person shuffles across a dry carpet, their body can be modeled as a charge 100-pF capacitance with one end grounded. Then, if the person touches a grounded metallic object such as a water faucet, the capacitance is discharged and the person experiences a brief shock. Typically, the capacitance may be charged to 20,000 V and the resistance (mainly of one's finger) is 100Ω. Determine the peak current during the discharge and the time constant of the shock.

So,
C=100 pF
V=20,000 V
R= 100 Ω

Homework Equations



T=RC

The Attempt at a Solution



I already Found T=.01 μS
just stuck at the peak current during discharge
 
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Well, when the "switch closes", so to speak, what initial voltage sees what resistance in its path on its way to ground?
 
gneill said:
well, when the "switch closes", so to speak, what initial voltage sees what resistance in its path on its way to ground?

200 a ?
 
Ryantruran said:
200 a ?

Make that 200 A (capital A for Amperes) and I'll agree :smile:
 
I attempted three times to make it capital. not sure why it won't let me. Thanks for the help
 

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