- #1
What is the potential difference between points A and B in a circuit?
- Thread starter kalupahana
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AI Thread Summary
The discussion focuses on calculating the potential difference between points A and B in a circuit with given EMFs and internal resistances. It concludes that if AB behaves like a short circuit, the potential difference will be zero, which is not a cause for concern. The relationship between current and resistance is explained using Ohm's Law, emphasizing that as resistance approaches zero, the potential difference must also approach zero to prevent infinite current. If a non-zero potential difference is calculated, it indicates a problem in the circuit. Understanding these principles is crucial for analyzing circuit behavior effectively.
- #2
Metaleer
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AB seems to be a shortcircuit. That is a potential difference of 0, so if you end up getting that, it's nothing to worry about. If you got something other than 0, that's when you should be worried. 
Basically, you can think of a shortcircuit as taking a branch with a single resistor R, and doing R → 0. From V = IR, you see that I = V/R, so if R → 0, the only way to stop I from going to infinity and being a defined finite value, is to have V = 0, that is, the potential difference across a shortcircuit vanishes.
Basically, you can think of a shortcircuit as taking a branch with a single resistor R, and doing R → 0. From V = IR, you see that I = V/R, so if R → 0, the only way to stop I from going to infinity and being a defined finite value, is to have V = 0, that is, the potential difference across a shortcircuit vanishes.
- #3
SammyS
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If VAB ≠ 0, then it would be I-i that goes to infinity.Metaleer said:AB seems to be a shortcircuit. That is a potential difference of 0, so if you end up getting that, it's nothing to worry about. If you got something other than 0, that's when you should be worried.
Basically, you can think of a shortcircuit as taking a branch with a single resistor R, and doing R → 0. From V = IR, you see that I = V/R, so if R → 0, the only way to stop I from going to infinity and being a defined finite value, is to have V = 0, that is, the potential difference across a shortcircuit vanishes.
- #4
Metaleer
- 123
- 0
The I in my explanation was the I of an arbitrary branch in which a shortcircuit is produced, I didn't use the same circuit as the one given. That's why I said V = IR, and not V = (I-i)R.
The I of my example would be extrapolated to whatever it need be, per particular circuit.
The I of my example would be extrapolated to whatever it need be, per particular circuit.
- #5
kalupahana
- 31
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Ok thanks for help, i got it
- #6
Metaleer
- 123
- 0
You're welcome. 
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system
$$M(t) = M_{C} + m(t)$$
$$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$
$$P_i = Mv + u \, dm$$
$$P_f = (M + dm)(v + dv)$$
$$\Delta P = M \, dv + (v - u) \, dm$$
$$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$
$$F = u \frac{dm}{dt} = \rho A u^2$$
from conservation of momentum , the cannon recoils with the same force which it applies.
$$\quad \frac{dm}{dt}...
I was told forces are vectors so they can be divided into x and y components, but what about the normal force or the force of static friction? do you divide those into x and y components if say you had a block that was lying on an angled surface?
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