What is the probability distribution for tossing a fair coin 4 times?

vanitymdl
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Homework Statement


Consider the experiment of tossing a fair coin 4 times. What is the probability distribution of the number X of heads?


The Attempt at a Solution


I got (0.5)(0.5)(0.5)(0.5) = 0.0625 but its wrong and I don't know why
 
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vanitymdl said:

Homework Statement


Consider the experiment of tossing a fair coin 4 times. What is the probability distribution of the number X of heads?

The Attempt at a Solution


I got (0.5)(0.5)(0.5)(0.5) = 0.0625 but its wrong and I don't know why
What you have calculated there is the probability of 4 heads, which is also the probability of zero heads (4 tails).

What is the probability of 3 heads? 2 heads, etc. ?
 
Write out in detail the "sample space" of the experiment (it will have 16 points). Count the number of heads for each of the 16 points. How many points are there in the event {2 heads}? What about for 1 head? For 3 heads?

RGV
 
In other words, the problem asked for the probability distribution, not just the probability of four heads. You also need P(three heads), P(two heads), P(one head), and P(no heads).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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