What is the recurrence relation for strictly increasing sequences from 1 to n?

AUCTA
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Homework Statement


Find a recurrence relation for the number of stricly increasing sequences of positive integers that have
1 as their first term and n as their last term, where n is a positive integer. that is, sequences a1, a2, ..., ak, where a1 = 1, ak = n, and aj < aj+1 for j = 1, 2, ...k - 1


Homework Equations



Just recurrences

The Attempt at a Solution



An = An-1 + An-2 + An-2 + An-3 + ... + An-k+ 1 since you j can equal 1, 2, 3, ... k - 1 and every step
allows for a recurrence for that given number of steps. I just do not think the solution can be made like that. I thought about something like writing every large jump in terms of single jumps but I am not sure.

Thanks in advance for your help
 
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If n is increased by 1, what sequences are possible that were not possible before? Can you think of a mapping between these and those that were already possible?
What sequences, if any, are no longer possible?
 
Any sequence including n + 1 is a new sequence.

For the mapping we can think about it like this :
Total = New + Old
Old = An-1 where n is effectively n + 1

I am not exactly sure on how to compute the number of new possible combinations
 
AUCTA said:
Any sequence including n + 1 is a new sequence.

For the mapping we can think about it like this :
No, that's not what I meant by a mapping. I mean a natural way of matching up new sequences with old ones.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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