What is the relation between the volume of liquid water and temperature?

AI Thread Summary
The discussion focuses on the mathematical relationship between the volume of liquid water and temperature, specifically referencing thermal expansion. The formula for thermal expansion is provided: change in volume equals the coefficient of volume expansion multiplied by the initial volume and the change in temperature. Additionally, the density of water in relation to temperature is highlighted, with a link to a resource for further information. Understanding this relationship is crucial for applications in various scientific fields. The conversation emphasizes the importance of precise formulas in studying the properties of water.
Werg22
Messages
1,431
Reaction score
1
It's all in the title. I'm looking for a mathematical relationship.
 
Physics news on Phys.org
werg,

what sort of relationship and under what circumstances? As stated there's not enuf to help you.
 
I think you are looking for the formula for thermal expansion.

change in volume=(coefficient of volume expansion)(initial volume)(change in temperature)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top