What is the relationship between Fourier transforms and Plancherel's theorem?

  • Thread starter Thread starter titaniumx3
  • Start date Start date
  • Tags Tags
    Fourier
titaniumx3
Messages
53
Reaction score
0
Fourier transform question

Homework Statement



http://img410.imageshack.us/img410/852/question3jh8.gif

Homework Equations



I will be using the following definitions and theorems:

http://img338.imageshack.us/img338/4173/moderatedecreasevd4.gif

http://img260.imageshack.us/img260/7461/fouriertransonmodzo5.gif

http://img338.imageshack.us/img338/3530/plancherelmodvv2.gif


The Attempt at a Solution



I've done part (a) and shown that the Fourier transform of f(x) is 4\,{\frac { \left( \sin \left( \pi \,\xi \right) \right) ^{2}}{{\xi}^<br /> {2}}} but on part (b) I am a bit lost. I know how to apply Plancherel's theorem but the function inside the modulus (i.e. {\frac { \left( \sin \left( \xi \right) \right) ^{2}}{{\xi}^{2}}}) is slightly different to the Fourier transform I got previously and I'm not sure how to relate them.

Please help!
 
Last edited by a moderator:
Physics news on Phys.org
BTW, I've shown f and it's Fourier transform are both functions of "moderate decrease". I'm also assuming you have to use part (a) to answer part (b). If not, how would you calculate something like that?
 
Last edited:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top