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[SOLVED] What is the resultant force and what is its consequent acceleration?
http://img48.imageshack.us/img48/4810/assignment503ij5.png
What is the resultant force acting on the object in the figure, and what is its consequent acceleration?
F = m.a
Vertical component = F\sin\theta
Horizontal component = F\cos\theta
http://img153.imageshack.us/img153/4963/assignment50301fq6.png
Horizontal Component = \cos{45} \times 60 = 42.4N
Vertical Component = \sin{45} \times 60 = 42.4N
http://img81.imageshack.us/img81/1580/assignment50302ns9.png
Horizontal Component = \cos{30} \times 60 = 52.0N
Vertical Component = \sin{30} \times 60 = 30N
Total Horizontal Component = 52 - 42 = 10N
Total Vertical Component = 42 - (30 + 5) = 7N
c^2 = a^2 + b^2
x^2 = 7^2 + 10^2
x = \sqrt{7^2 + 10^2}
x = 12.2N
F = m.a
a = \frac{F}{m} = \frac{12.2}{5.0} = 2.4ms^{-2}
Is my answer correct?
Homework Statement
http://img48.imageshack.us/img48/4810/assignment503ij5.png
What is the resultant force acting on the object in the figure, and what is its consequent acceleration?
Homework Equations
F = m.a
Vertical component = F\sin\theta
Horizontal component = F\cos\theta
The Attempt at a Solution
http://img153.imageshack.us/img153/4963/assignment50301fq6.png
Horizontal Component = \cos{45} \times 60 = 42.4N
Vertical Component = \sin{45} \times 60 = 42.4N
http://img81.imageshack.us/img81/1580/assignment50302ns9.png
Horizontal Component = \cos{30} \times 60 = 52.0N
Vertical Component = \sin{30} \times 60 = 30N
Total Horizontal Component = 52 - 42 = 10N
Total Vertical Component = 42 - (30 + 5) = 7N
c^2 = a^2 + b^2
x^2 = 7^2 + 10^2
x = \sqrt{7^2 + 10^2}
x = 12.2N
F = m.a
a = \frac{F}{m} = \frac{12.2}{5.0} = 2.4ms^{-2}
Is my answer correct?
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