What is the resulting current in a series circuit with a resistor and capacitor?

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The discussion focuses on calculating the resulting current in a series circuit with a resistor and capacitor, given their impedances and a sinusoidal voltage of 240 V (RMS). The initial attempt at the solution incorrectly used 250 instead of 240 in the formula for current, which should be I = 240/sqrt(330^2 + 318^2). Participants noted that while the magnitude of the current was determined, the phase angle was not addressed. There is a request for further explanation on how to calculate the phase of the current. The conversation highlights the importance of accuracy in calculations and understanding both magnitude and phase in AC circuits.
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I have solved it (:

Homework Statement


Ir=Impedance of a resistor = 330
Ic=Impedance of a capacitor=318
V= Sinusoidal Voltage = 240 V (RMS) is applied across the series combination.
calculate the resulting current.

Homework Equations


Not sure

The Attempt at a Solution


I am really not sure how I would work out the resulting current.
Answer
I = 250/sqrt(330^2+318^2)
 
Last edited:
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I have solved it (:
Well done.
Please help others by explaining how you got the answer.
 
Should be 240/sqrt(330^2 + 318^2).
Also, you have determined the magnitude of the current but not its phase.
 
yes, sorry it's supposed to be 240 not 250. I am not sure what its phase is
 
patep023 said:
I am not sure what its phase is

Gonna take a shot at it?
 
Will do tomorrow
 

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