What is the solution to question 2 on energy conservation problems homework?

AI Thread Summary
The discussion focuses on solving question 2 of an energy conservation homework problem. The user attempted to apply the energy conservation rule, determining the speed as √2gh, but struggled with finding the angle after the object passes through. They noted that the parabola's equation, y=ax^2, is crucial for further calculations. By using the given point B at (2H, H), they can compute the value of a and find the slope at point B. The conversation emphasizes the importance of incorporating the parabola equation in the solution process.
Mzaa
Messages
4
Reaction score
1

Homework Statement


https://www.img.in.th/image/VNYMHY
https://www.img.in.th/image/VNYKDv
This is my homework,but I have a problems with question no.2

Homework Equations

The Attempt at a Solution


I tried to used energy conservation rule to get that the speed is √2gh ,but I don't know how to know the angle after that passing through.
 
Physics news on Phys.org
The parabola has the form ## y=ax^2 ##. They give you that the point B is at ## (2H,H) ##. That will allow you to compute ## a ## and thereby get the slope at ## B ##.
 
  • Like
Likes Mzaa
Thank you so much! I really forget to use parabola equation.
This is really helpful.
 
  • Like
Likes Charles Link
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top