What is the speed of an electron in the Bohr model of the hydrogen atom?

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In the Bohr model of the hydrogen atom, the speed of an electron is calculated based on its circular motion around a proton, with a radius of 5.3e-11 m. The relevant equations include angular momentum and centripetal force, leading to the formula v = n(h/2pi)/(rm). The initial calculation yielded a surprisingly low speed, prompting a reevaluation of the radius used, which was miswritten as 5.3e-4 instead of the correct 5.3e-11. After correcting this error, the calculated velocity became significantly larger and more reasonable for an electron's speed. Accurate notation is crucial in physics calculations to avoid errors.
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[SOLVED] speed of electrons

Homework Statement



In the Bohr model of the hydrogen atom, an electron circles a proton at a radius of 5.3e-11 m. How fast must the electron be moving if the centripetal acceleration is to be supplied by Coulombic attraction?

Homework Equations



L=n(h/2pi) where h is Plancks constant and n is an integer

L=rmv


The Attempt at a Solution



n(h/2pi)=rmv

v=n(h/2pi)/(rm)

v= n(6.63e-34/2pi)/(5.3e-4)(9.11e-31)

v= 0.218n m/s

Now that velocity seems way to small for a speed of an electron...

Any help is appreciated! Thanks!
 
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v= n(6.63e-34/2pi)/(5.3e-4)(9.11e-31)

Why is this a 4 instead of an 11?
 
Thank you...My 11 looked like a 4 in my notes...simple mistakes can kill you! haha

I got a very large velocity now so the answer makes more sense.
 

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