What is the speed of the crate when it reaches the bottom?

  • Thread starter Thread starter physx_420
  • Start date Start date
  • Tags Tags
    Speed
Click For Summary

Homework Help Overview

The problem involves a crate sliding down an inclined plane, with a focus on determining its speed at the bottom. The crate has a mass of 20.0 kg, the incline is 3.00 m high, and friction is considered negligible.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to identify the necessary angle to calculate the force parallel to the incline but expresses uncertainty about how to proceed without it. Some participants suggest using conservation of energy principles instead of focusing on work done.

Discussion Status

Participants are exploring different approaches to the problem, with some suggesting that the height of the incline is sufficient for calculating the final speed without needing the length of the incline. There is an acknowledgment that mass does not affect the final speed under the given conditions.

Contextual Notes

The discussion highlights the assumption of negligible friction and the implications this has on the energy considerations for the problem. There is also a note about the lack of an angle provided in the problem statement, which is causing some confusion for the original poster.

physx_420
Messages
32
Reaction score
0

Homework Statement


A 20.0-kg crate slides down an inclined plane that is 3.00-m high and 20.0-m long. If friction is negligible, what is the speed of the crate when it reaches the bottom of the plane?



Homework Equations


W= F*D
K= 1/2 m*(v^2)


The Attempt at a Solution


They don't give me an angle so I'm not sure how I'm supposed to go about solving for the force parallel to the inclined plane. Once I have that I'll be able to finish out the problem. Help please!
(The answer turns out to be 7.67 m/s; I just need to know how to get there)
 
Physics news on Phys.org
Just use conservation of energy. You have gravitational potential energy in the beginning. Don't bother with the work [tex]W=FD[/tex].
 
Ahhh, ok I see. Thanks a lot N-gin!
 
The 20 M long is not needed for this problem because the friction is assumed to be zero. No energy is lost in friction and so M*g*H = (1/2)*M*V^2

So V = sqrt(2*g*H)

So the velocity is independent of the Mass!

If you had friction, then still mass is irrelevant.
 

Similar threads

Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
10
Views
5K