What is the stress within the column?

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The discussion focuses on calculating the stress and strain within a marble column supporting a mass of 30,000 kg. The stress is determined using the formula stress = force/area, resulting in 172,941 N/m². For strain, the relationship with stress is established through the elastic modulus, leading to the equation strain = stress/Y, where Y is the elastic modulus of marble. The strain is calculated as 3.5e-6, emphasizing the importance of significant figures in the final answer. The conversation highlights the distinction between using elastic and shear modulus depending on the type of stress being analyzed.
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Homework Statement



A marble column of cross-sectional area 1.7 m2 supports a mass of 30,000 kg.
(a) What is the stress within the column?
(b) What is the strain?

Elastic modulus for marble E (N/m^2) 50e9
shear modulus (G)

Homework Equations



a)stress=F/A=N/m^2
b) don't know

The Attempt at a Solution



a) 30000*9.8/1.7=172941 N/m^2 (this is right)
b)
 
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The strain will be given by the change in the length of the column divided by its initial length: \frac{\Delta L}{L_0}.

Its relation to the stress is given by: \frac{F}{A} = Y \frac{\Delta L}{L_0}. That is, the stress is equal to the modulus times the strain. Now its just algebra.
 
how do you find the length of the column?
 
You don't need it. You can just treat \frac{\Delta L}{L_0} as a single term, does that make sense?
 
so just solve for that term then? what would Y be? the elastic or shear modulus?

F=30000*9.8
A=1.7
Y=?
 
You would use the elastic modulus, we're speaking in terms of tensile stress and strain. If we were using shear stress and strain, we would use the shear modulus.
 
Last edited:
so-

(30000*9.8/1.7)/50e9=3.5e-6
 
Looks good to me, don't forget to put your answer for part a into significant figures.
 
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