What is the Time of Death Based on Newton's Law of Cooling?

[blueparukia]

Homework Statement

A man was murdered and inspectors found his body temperature to be 88 degrees at 4:30AM.
Climate control in the room was set to 76 degrees.

Temperature of his body was taken again 2 hours later and found to be 85.8 degrees.

The standard body temperature for human beings is 98.6 degrees.

Need to find the time at which the man was killed (so when his temperature was 98.6)

Homework Equations

T = (T0-Tm)e^(-kt) + Tm

Where T0 = Initial temperature of the body (failry sure this is 98.6 degrees)
and Tm = Temperature of the surrounding medium (76 deg
rees)


I missed the lesson and this is catchup work and I'm having trouble grasping how to use logs/natural logs to solve for t.

Thank you very much.

 

[gomunkul51]

http://www.sosmath.com/diffeq/first/application/Newton/Newton.html

Good Luck :)

 

[blueparukia]

Wow, pretty specific example there.

Thanks.