What is the value of y in this water tank pressure problem?

AI Thread Summary
The discussion revolves around calculating the value of y in a water tank pressure problem, with uncertainty about whether to include atmospheric pressure. It is clarified that whether atmospheric pressure is considered depends on whether the pressure gauge measures absolute or gauge pressure. Participants agree that the additional height of 1 meter should be included in the calculations, adjusting the pressure contributions accordingly. The final equation presented is 30000 + (1.5x820x9.81) + (6 x1000x9.81) = 13600(9.81)y, confirming the inclusion of the extra meter. The conclusion emphasizes the importance of understanding gauge pressure in solving the problem accurately.
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Homework Statement


i am asked to find the value of y in this question . I am not sure should i consider the atmospheric pressure acting on the mercury or not .

Homework Equations

The Attempt at a Solution


i choose to consider the atmospheric pressure as 0 in this case . So , my working is 30000 + (1.5x820x9.81) + (5 x1000x9.81) =13600(9.81)y , where y = 0.68m , am i right ? btw , i am not very sure about whether the pressure of water is (5 x1000x9.81) or not , because the outlet is not at bottom of teh tank , can someone exp;lain pls ?
 

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If the pipe were even lower than the 1m shown (say 100m lower) would the pressure at the water-mercury interface be affected? So should you account for that 1m height by adding it to the 5m?

Wether you can ignore atmospheric pressure depends on if the pressure gauge is showing absolute pressure or pressure relative to atmospheric ('gauge' pressure).
 
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billy_joule said:
If the pipe were even lower than the 1m shown (say 100m lower) would the pressure at the water-mercury interface be affected? So should you account for that 1m height by adding it to the 5m?

Wether you can ignore atmospheric pressure depends on if the pressure gauge is showing absolute pressure or pressure relative to atmospheric ('gauge' pressure).
i think the extra 1m should take into consideration , am i right ? so , the working should be 30000 + (1.5x820x9.81) + (6 x1000x9.81) =13600(9.81)y ?
 
foo9008 said:
I think the extra 1m should take into consideration , am i right ?
Yes.
So, the working should be 30000 + (1.5x820x9.81) + (6 x1000x9.81) =13600(9.81)y ?
OK if the 30 kPa is gauge pressure.
 
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