What is the Velocity of the Balloon When a Man Moves Up a Ladder Attached to It?

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SUMMARY

The discussion centers on the physics problem involving a man of mass m moving up a ladder attached to a balloon of mass M. The derived equations indicate that the velocity of the balloon, u, is calculated using the formula u = -mv/(M+m), demonstrating that the balloon moves downward when the man ascends. This conclusion is based on the principle of conservation of momentum, confirming that as the man moves upward, the balloon must descend to maintain the center of mass in a static position.

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Homework Statement


It says that "a man of mass m is standing on a ladder attached to the rope of a balloon of mass M (weight of the ladder and rope can be neglected). The balloon is in a static position. Now the man starts moving upwards through the ladder with a velocity v with respect to the balloon. Now what will be the velocity of the balloon ?"

Homework Equations



Now if the velocity of the balloon and the man with respect to the ground be u and V respectively, then we can say

V - u = v

V = u + v

now if we use the conservation of mementum, then

Mu + m(u + v) = 0

(M+m)u = - mv

u = - mv/(M+m)

Is it right ? This indicates that the balloon will go downwards !

The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution

 
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hi subho123! :wink:
subho123 said:
u = - mv/(M+m)

Is it right ? This indicates that the balloon will go downwards !

and why not??

the centre of mass stays in the same place, so if the man goes up, the balloon must go down!

looks fine to me :smile:
 
Thanks for ur reply sir...
 

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