What is the velocity of the swinging pendulum?

AI Thread Summary
The discussion focuses on calculating the velocity of a pendulum swinging at a 25.5-degree angle with a mass of 14.6 kg and a string length of 0.5 m. The radius of the circular motion was determined to be 0.215 m, and the gravitational force was calculated to be 143.08 N. Participants emphasized the importance of separating the forces into x and y components, noting that centripetal force is not a distinct force but a result of other forces acting on the mass. By applying Newton's second law and using trigonometric relationships for tension, the x-component of the tension was found, leading to a calculated speed of approximately 1.004 m/s. The discussion highlights the necessity of correctly setting up force equations to solve for velocity in pendulum motion.
thakkar1016
Messages
2
Reaction score
0

Homework Statement


31acc572-0f53-4985-9649-a305cfa5e7c1.gif

The pendulum is swinging at an angle of 25.5 degrees (with respect to the vertical)
The mass of the object is 14.6 kg
Length of String is .5 m
Find the velocity (v = ?)

Homework Equations


Centripetal Acceleration (ac) = v^2/r
Centripetal Force (Fc) = m*ac


The Attempt at a Solution


I'm getting stuck at this problem after a certain point. I've found the radius of the circle using the right angle trig identities.
R = .215 m

I also know that the problem has to do with the sum of the forces of Fcp, Tension, and Force due to Gravity.
The y-component of the forces should be 0, so Fg (force of gravity) minus y component of Tension equals 0.

Therefore, I know that Fg = 143.08, and the y-component of Tension = 143.08.
However, I'm having trouble figuring out what to do for the x-component of the forces, so that I can use it to find the velocity.
 
Physics news on Phys.org
What would the tangent of the angle tell you? If you're solving for "v" in the centripetal force equation, keep in mind this is the speed of the ball rather than the velocity, in which case we need not consider x and y components.
 
u need set up the equations into two parts x, y

the x component of this pendulum would be
Fx = ma = Tx-mr^2/R = 0
where Tx is your x-component of the tension
the sum of the horizontal forces must equal to zero in order for the ball to move in the circle

Fy = ma = Ty-mg = 0
the sum of the veritcal forces must equal to zero in order for the ball to stay on the string
 
conical pendulum

thakkar1016 said:

The Attempt at a Solution


I'm getting stuck at this problem after a certain point. I've found the radius of the circle using the right angle trig identities.
R = .215 m
Good.
I also know that the problem has to do with the sum of the forces of Fcp, Tension, and Force due to Gravity.
Careful here. Only two forces act on the mass: Weight and string tension. (Centripetal force is not a separate force, just the name given to any force that creates a centripetal acceleration.)
The y-component of the forces should be 0, so Fg (force of gravity) minus y component of Tension equals 0.
Good.

Therefore, I know that Fg = 143.08, and the y-component of Tension = 143.08.
Since you know the angle of the string, you also know the full value of the tension. But you don't really need to calculate it. (See below.)
However, I'm having trouble figuring out what to do for the x-component of the forces, so that I can use it to find the velocity.
Apply Newton's 2nd law. For the x-direction, the acceleration is not zero.

Set up your two force equations (for x and y) and combine them to solve for v.

Hint: Express the x and y components of the tension as T\sin\theta and T\cos\theta. There's no need to calculate T (unless they ask for it).
 
Thanks. I ended up finding the x-component of the Tension Force, and used it to find the acceleration in the x-direction. From there I used the centripetal acceleration to get about 1.004 m/s for the speed.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top