What is the Vertical Force on the Support Closest to the Piano?

AI Thread Summary
To determine the vertical force on the support closest to a piano resting on a horizontal beam, the principle of equilibrium is applied, which states that the net force and net torque must be zero. The total weight of the beam (160 kg) is calculated to be 1568 N, while the piano (300 kg) contributes an additional 392 N. By setting up the equilibrium equation for vertical forces, the vertical force on the support closest to the piano is found to be -1960 N, indicating a downward force. This calculation illustrates how the weights of both the beam and piano affect the support forces. Understanding these principles is essential for analyzing similar scenarios in physics.
pupatel
Messages
11
Reaction score
0
A 160 kg horizontal beam is supported at each end. A 300 kg piano rests a quarter of the way from one end.
What is the vertical force on the support closest to the piano?

How do i do this? :confused:
 
Physics news on Phys.org
conditions for equilibrium

Consider that for equilibrium:
(a) Net force must be zero
(b) Net torque about any point must be zero
 


To calculate the vertical force on the support closest to the piano, we need to use the principle of equilibrium in physics. This states that the sum of all forces acting on an object must be equal to zero in order for it to be in a state of equilibrium.

In this scenario, the beam is in equilibrium since it is not moving or rotating. This means that the total vertical forces acting on the beam must be equal to zero.

Let's start by calculating the total weight of the beam and piano combined. The weight of the beam can be calculated by multiplying its mass (160 kg) by the acceleration due to gravity (9.8 m/s^2), giving us a weight of 1568 N.

Next, we need to find the weight of the piano. Since it is resting a quarter of the way from one end, we can assume that the distance from the support closest to the piano to the piano itself is one quarter of the total length of the beam. This means that the weight of the piano would be one quarter of the weight of the beam, which is 392 N.

Now, we can set up an equation to find the vertical force on the support closest to the piano:

Total vertical forces = Weight of beam + Weight of piano + Vertical force on support closest to piano

Since the beam is in equilibrium, the total vertical forces must be equal to zero. We already know the weight of the beam (1568 N) and the weight of the piano (392 N), so we can plug those values into the equation:

0 = 1568 N + 392 N + Vertical force on support closest to piano

Solving for the vertical force on the support closest to the piano, we get:

Vertical force on support closest to piano = -1960 N

This means that the vertical force on the support closest to the piano is 1960 N in the downward direction. This is due to the weight of the beam and piano pulling down on the support.

In summary, using the principle of equilibrium, we can calculate the vertical force on the support closest to the piano by considering the weight of the beam and piano and setting them equal to the total vertical forces acting on the beam. This helps us understand the distribution of forces in a vertical force scenario and can be applied to other similar problems.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top