What is the Wien bridge frequency proof and how do you solve it?

AI Thread Summary
The discussion focuses on solving the Wien bridge frequency proof, specifically how to determine the frequency when the bridge is balanced. The key equation derived is based on the impedances of the circuit components, leading to a complex equation that requires equating real and imaginary parts. Participants share their attempts at calculating the impedances, with one user successfully simplifying their approach by focusing on the real parts of the equation. Ultimately, the solution involves balancing the equation to find the frequency using the relationship between the resistances and capacitances in the circuit. The thread concludes with a resolution to the problem through careful manipulation of the impedance values.
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[SOLVED] Wien Bridge Frequency Proof

Homework Statement



The ac bridge circuit shown is called a Wien bridge (also Wein bridge).
Wien Bridge.png


Show that when the bridge is balanced, frequency is found by the Eqn attached.
Eqn.png

Homework Equations



w=2*pi*f

Using the number from each branch as a guide, the general solution to AC bridges is Z4 = (Z3/Z1)*Z2

The Attempt at a Solution



I keep trying to solve for impedences to plug into the second equation provided, but my j values do not cancel and the equation left is rather messy (R2R4C2C4*w^2 +jw(RzR4C2 -R2C2 -R4C4) +1 = 0.

For my impedence values I have been using
Z1 = R1
Z2 = R2 -j/wC2
Z3 = R3
Z4 = (R4/jwC4)/(R4 +jwC4)

Any help with this would be greatly appreciated.
 
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I think Z_4 = \frac {-jR_4} {\omega C_4 (R_4 - \frac{j}{\omega C_4})}


Both the real and the imaginary parts of Z4 = (Z3/Z1)*Z2 must be 0
 
Actually, I think our Z4 values are the same, since -j = 1/j. But thank you! I managed to figure it out after you got me thinking about real and imaginary parts.

It's fairly simple, actually: I just had to equate the real parts from my equation so that R2R4C2C4*w^2 + 1 = 0 (and then I took absolute value).
 
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