What is the work done by an ideal gas in an isobaric process?

AI Thread Summary
In an isobaric process, the work done by an ideal gas can be calculated using the formula W = p(V2 - V1). For a gas heated from 27°C to 107°C at constant pressure, the calculation involves the ideal gas law. The initial attempt yielded a work value of 1300 J, but the correct answer, as per the textbook, is 1330 J. The discrepancy was resolved by using the equation W = nRΔT, which aligns with the textbook solution. Accurate calculations are essential for obtaining the correct work done in thermodynamic processes.
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[SOLVED] Isobaric process

Hi, need some help with this.

I got to moles of an ideal gas that are heated at constant pressure from T=27 C to T=107C.

How do I calculate the work done by the gas?

I know that for a isobaric process the work is given by

W = p(V2-V1)

Thanks
 
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HINT: Ideal gas law

P.S. We have Homework & Coursework forums for textbook questions.
 
Oh, I'm sorry. Yeah, I tried W = nRT.

Came out with 1300 J, but the key book says 1330 J.
 
Using W = nR\Delta T, my answer agrees with your text. I would suggest you re-check your calculations.
 
There, it worked.
 

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