What is the work done by gravitation

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Homework Help Overview

The discussion revolves around calculating the work done by various forces acting on a skier's cart as it moves down a slope. The subject area includes concepts of work, gravitational force, friction, and the implications of constant speed in a physics context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the work done by friction, the rope, gravitation, and the total work, raising questions about the implications of constant speed on these calculations.
  • Some participants question the definition of work and its relationship to force and distance, particularly in the context of constant speed.
  • Others suggest clarifying the calculations for work done by different forces and the significance of angles in those calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of work and its calculations. Some guidance has been provided regarding the definition of work and the importance of considering individual forces, but no consensus has been reached on the specific calculations or implications of constant speed.

Contextual Notes

Participants are working within the constraints of a homework problem, which includes specific values for mass, distance, angle, and friction coefficient. There is uncertainty regarding the displacement in the context of gravitational work and the overall total work due to the constant speed of the cart.

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A skier lowers a cart 30m down a slope with a sontant speed. The cart has a mass of 90kg. The angle of the slope is 60 degrees. The coefficient of friction is 0.100.
A)Find the work done by friction as the sled moves down the hill.
B) how much work is done by the rope on the sled.
C) What is the work done by gravitation.
D) What is the total work done.

A) I already calculated friction, which was uN with N=mgcos , which gave me -1323J
But I am not sure about the next 3 parts
B) Would work be zero since speed is constant?

C) WG= FgD=mgd= (90kg) (9.8m/s2) is displacement 0m?

D) Would total work be zero, since speed is constant?
 
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How is work defined?

ehild
 


Work is Force * distance.

But since speed is constant, does that mean the total work is 0, since there would be no force?
Or would total work still be the addition of the separate works.
 


The total work of all the forces acting on the sled is zero, but the work of the separate forces is not.
Take care when calculating work. It is W=F d cos (theta), theta being the angle between the force F and displacement d.

ehild
 

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