What is the work done by gravitation

AI Thread Summary
The discussion revolves around calculating the work done by various forces acting on a skier's cart moving down a slope. The work done by friction was calculated as -1323J, but there is uncertainty regarding the work done by the rope and gravitational forces. It is noted that since the skier moves at a constant speed, the net work could be zero, suggesting that the forces are balanced. However, individual work contributions from friction, gravity, and the rope still exist and should be calculated separately. The importance of understanding how work is defined and calculated, particularly in relation to force and displacement, is emphasized.
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A skier lowers a cart 30m down a slope with a sontant speed. The cart has a mass of 90kg. The angle of the slope is 60 degrees. The coefficient of friction is 0.100.
A)Find the work done by friction as the sled moves down the hill.
B) how much work is done by the rope on the sled.
C) What is the work done by gravitation.
D) What is the total work done.

A) I already calculated friction, which was uN with N=mgcos , which gave me -1323J
But I am not sure about the next 3 parts
B) Would work be zero since speed is constant?

C) WG= FgD=mgd= (90kg) (9.8m/s2) is displacement 0m?

D) Would total work be zero, since speed is constant?
 
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How is work defined?

ehild
 


Work is Force * distance.

But since speed is constant, does that mean the total work is 0, since there would be no force?
Or would total work still be the addition of the separate works.
 


The total work of all the forces acting on the sled is zero, but the work of the separate forces is not.
Take care when calculating work. It is W=F d cos (theta), theta being the angle between the force F and displacement d.

ehild
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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