What Is Theta Critical for an Object on an Inclined Plane?

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Theta critical for an object on an inclined plane is determined by the relationship between static friction and gravitational forces acting on the object. The equations provided indicate that sliding begins when the static frictional force equals the maximum static friction, expressed as μ_s * F_n, where F_n is the normal force. The critical angle (theta critical) can be found by setting μ_s * mgcos(theta) equal to mgsin(theta), leading to the conclusion that μ_s = tan(theta). This means that the angle of inclination at which an object starts to slide is directly related to the coefficient of static friction. Understanding these relationships is crucial for solving problems involving objects on inclined planes with friction.
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We have Uk and/or Us and angle of inclination (theta)


Are these eq-ns relevant? sin(theta critical)=Us(tan(theta critical))=Us
and sin(theta static)/cos(theta static)=Uk(tan(theta static)=Uk



How do I even interpret these eq-ns? Exam is tomorrow and I need to know how to find the angle of inclination that allows an object to start sliding (theta critical) and the angle of inclination so that the object will slide w/o accelaration. This is for an object on an inclined plane w/ friction.
 
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I'm confused by the equations you wrote... can you write them exactly as they are?

The moment when sliding occurs is when the static frictional force becomes \mu_s*F_n.

Take the equation perpendicular to the plane... F_n - mgcos(\theta) = 0, so F_n = mgcos(\theta)

The equation parallel to the plane is: mgsin(\theta) - f = 0

so this is while the block is not sliding...

ie: f = mgsin(\theta) (1)

so this equation is always true while the block is not sliding... you will notice that as theta becomes larger (the incline becomes steeper)... f becomes larger... this is all while the block is still not sliding... but there is a limit to how long this can go on... the limit occurs when f becomes \mu_s*F_n = \mu_s*mgcos(\theta).

so to find the angle at which this limit occurs substitute f = \mu_s*mgcos(\theta) into (1)

so you get:

\mu_s*mgcos(\theta) = mgsin(\theta)

\mu_s = tan(\theta)
 
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