What limit must the force excede if we want to separate two bodies + friction

AI Thread Summary
To separate the weight from the plank on a leveled base, the applied force must exceed 14.7 N. This calculation considers the friction between the plank and the base (0.4) and the friction between the weight and the plank (0.3). The force required to overcome the friction between the plank and the base is 11.76 N, while the force needed to move the weight on the plank is 2.94 N. Adding these forces gives the total required force of 14.7 N. Therefore, a force greater than 14.7 N is necessary for the weight to slip off the plank.
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Homework Statement



On a leveled base is a plank with a mass M = 2 kg, on the plank is a weight with a mass m = 1 kg. What limit must the force exceed, when we pull the plank in a horizontal direction for the weight to slip from the plank? Ratio of friction between the plank and the base is k1 = 0.4 and ratio of friction between the weight and the plank is k2 = 0.3.


Homework Equations



N= mg
Fk= μkN

The Attempt at a Solution



M= 2 kg
m= 1 kg
μk1= 0.4
μk2= 0.3

For the plank and weight to start moving: F1= (M+m)gμk1= 11.76 N
For the weight to start moving on the plank: F2= mgμk2= 2.94 N

So if my logic works correctly I simply add the two forces and the force will be big enough for the weigh to start falling off the plank.

F= F1 + F2= 11.76N + 2.94 N= 14.7 N

And the answer would be: The force have to be bigger than 14.7 N for the weight to fall off the plank.
 
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