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What time does the grinding wheel stop spinning? (constant ang. accel.)

  1. Jul 30, 2010 #1
    1. The problem statement, all variables and given/known data
    At t=0, a grinding wheel has omega=24.0rad/s, alpha=30.0rad/s^2 until a circuit breaker trips at t=2s. From then on it turns through 432rad as it coasts to a stop at constant alpha.
    a) through what total angle did the wheel turn between t=0 and the time it stopped?
    b) what time did it stop?
    c) what was its acceleration as it slowed down?


    2. Relevant equations
    theta-f.=theta-in. + omega*t + 1/2*alpha*t^2
    omega-f.^2=omega-in.^2 + 2*alpha*(theta-f. - theta-in.)
    [-B+sqrt(b^2 - 4AC)]/2A

    3. The attempt at a solution
    for a) I solved theta-f.(2) to get 540 radians.
    for b) I plugged in the final value of theta and moved everything over so I could use the quadratic equation to get t=.5 sec, but the answer is 12.3 s...I'm not sure where I went wrong. Help please
     
  2. jcsd
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