- #1
Jared94
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Hi there, I've forgotten how to solve these problems, eg:
If I've got two shafts, two wheels per shaft meaning four wheels in total, each wheel is 60 mm in diameter, and the power consumed by the system in providing a constant horizontal velocity of 0.15 m/s is 200W, what is the torque in each wheel? The wheels are rubber coated, and the wheels are acting upon a steel surface (take coefficient of friction to be 0.7).
This is how I've solved the problem:
Power = Torque x angular velocity
w = v / r = 0.15 / 0.030 = 5 rad/s
Torque = P / w = 200 / 5 = 40 Nm
Now since there are 4 wheels (instead of just 1 wheel) AND two shafts with two wheels in each shaft, how do I interpret this torque of 40 Nm? Is the force per wheel just force = Power / velocity or is this force divided amonst the 4 wheels?
With the friction, since the system is moving at a constant speed of 0.15 m/s, will the thrust force equal the frictional forces? The force here doesn't equal the force calculated via the torque of 40 Nm, is this because of a transmission efficiency?
Thanks in advance, really annoying how I still haven't grasped these basic concepts (I'm studying Mechatronics engineering at uni)
If I've got two shafts, two wheels per shaft meaning four wheels in total, each wheel is 60 mm in diameter, and the power consumed by the system in providing a constant horizontal velocity of 0.15 m/s is 200W, what is the torque in each wheel? The wheels are rubber coated, and the wheels are acting upon a steel surface (take coefficient of friction to be 0.7).
This is how I've solved the problem:
Power = Torque x angular velocity
w = v / r = 0.15 / 0.030 = 5 rad/s
Torque = P / w = 200 / 5 = 40 Nm
Now since there are 4 wheels (instead of just 1 wheel) AND two shafts with two wheels in each shaft, how do I interpret this torque of 40 Nm? Is the force per wheel just force = Power / velocity or is this force divided amonst the 4 wheels?
With the friction, since the system is moving at a constant speed of 0.15 m/s, will the thrust force equal the frictional forces? The force here doesn't equal the force calculated via the torque of 40 Nm, is this because of a transmission efficiency?
Thanks in advance, really annoying how I still haven't grasped these basic concepts (I'm studying Mechatronics engineering at uni)