When the pot is on the point of slipping

[jk2455]

A student in a pottery class leaves a freshly baked clay pot to cool down on a rotating
platform. If the pot is positioned at 9cm away from the center, how fast does the platform
rotate (in units of revolutions per seconds) when the pot is on the point of slipping?
Assume that the coefficient of static friction between the pot and the platform is µs = 0.3.


answer -->0.91 rev/sec
i do not really understand this question or what is the right formula to use

 

[berkeman]

A student in a pottery class leaves a freshly baked clay pot to cool down on a rotating
platform. If the pot is positioned at 9cm away from the center, how fast does the platform
rotate (in units of revolutions per seconds) when the pot is on the point of slipping?
Assume that the coefficient of static friction between the pot and the platform is µs = 0.3.


answer -->0.91 rev/sec
i do not really understand this question or what is the right formula to use

The relevant equations are the friction equation (relates friction force to the friction coefficient and the normal force [weight] of an object), and the equation for centripetal acceleration in uniform circular motion. Does that help? Write down those equations, and see if that gets you going on this problem.