When Will the Motorcycle Catch Up to the Car?

AI Thread Summary
The discussion focuses on a physics problem involving a car and a motorcycle, where the car travels at a constant speed of 20 m/s while the motorcycle accelerates from rest at 2 m/s². Participants suggest using the kinematic equation for position to find when the motorcycle catches up to the car. They emphasize the importance of expressing the positions of both vehicles as functions of time and solving for when these positions are equal. Additionally, there is a clarification regarding the initial positions of both vehicles, confirming that they start from the same point. The conversation highlights the need for understanding motion graphs and areas under the curves to visualize the problem.
lexi
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1. Homework Statement ---------->
At a time = 0, a car has a constant velocity of 20 m/s east. At the same time a motorcycle starts from rest in the same direction with an accelerationof 2 m/s2. How long does it take the motorcycle to catch up with the car, and what distance have they traveled by that time?

2. Homework Equations



3. The Attempt at a Solution

Do you use the equation: x-x0 = v0t + 1/2at^2?

Please help! I really want to learn this so if you could show me the steps that would be great! How do you know what equation to use??

Thanks!
 
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lexi said:
At a time = 0, a car has a constant velocity of 20 m/s east. At the same time a motorcycle starts from rest in the same direction with an accelerationof 2 m/s2. How long does it take the motorcycle to catch up with the car, and what distance have they traveled by that time?
I presume the car has a head start! If the motorcycle is at x=0 at t=0, where is the car at that time?

Write expressions for the position of each as a function of time. Then solve for the time when their positions are equal.
 
Doc Al said:
I presume the car has a head start! If the motorcycle is at x=0 at t=0, where is the car at that time?
Of course, the car doesn't have to have a head start. (My bad.) I guess that's what you meant. In which case, at t=0 both are at x=0.
 
Sketch the graphs of motion and then look at areas under graphs...no need for equations as such.
 
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