Where Does the Electric Field Between Two Charges Equal Zero?

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Homework Statement


Two particles having charges q1 = 0.600 nC and q2=5.50 nC are separated by a distance of 1.10 m.

At what point along the line connecting the two charges is the total electric field due to the charges equal to zero?


Homework Equations


Coulomb's Law


The Attempt at a Solution



i have no clue. I know that d = 1.10m. But how do I start the problem. Any suggestions would be nice..thanks in advance.
 
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1. Can you write down the expression for the electric fields of the two charges separately?

2. What do you think is meant by the phrase "total electric field due the charges"?

Think about what you're doing.
 
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This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
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The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
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