Where is the maximum electric field on the axis of a charged ring?

AI Thread Summary
The maximum electric field along the axis of a uniformly charged ring occurs at x = a/(sqrt2) and has a magnitude of Emax = Q/(6(sqrt3)πε0a^2). The discussion highlights the need to consider the cancellation of vertical components of the electric field from the ring's top and bottom. Participants express confusion regarding the appropriate equations and methods to solve the problem. Clarification and detailed steps are requested to aid understanding. The conversation emphasizes the complexity of the problem and the importance of clear problem-solving strategies.
leroyjenkens
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Homework Statement


Show that the maximum magnitude Emax of the electric field along the axis of a uniformly charged ring occurs at x=a/(sqrt2) and has the value Q/(6(sqrt3)πε0a2)


Homework Equations


E=keΔq/r2


The Attempt at a Solution


I made the vertical components cancel along the axis from the top and bottom of the ring so that I just have the x-axis field, but I really don't know what else to do. I'm not even sure if that equation is the right one to use. This question seems to be made deliberately confusing.
 
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Show your work in detail, please.

ehild
 

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