Where Will a Proton Move When Facing an Electric Field?

AI Thread Summary
A proton moving at 3.8 x 10^5 m/s enters an electric field of 5.6 x 10^4 N/C directed to the left. To determine how far the proton travels before its speed reaches zero, the force exerted on the proton can be calculated using the equation F = E*q, where E is the electric field and q is the charge of the proton. Once the force is known, the acceleration can be derived using F = ma, allowing for the application of kinematic equations to find the distance traveled. The subsequent motion of the proton will involve it decelerating to a stop due to the opposing electric field. Understanding these principles will help in accurately describing the motion of the proton in the electric field.
samblue
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Homework Statement



A proton moving to the right along the x-axis at 3.8*10^5m/s, enters a region where the electric field of intensity 5.6*10^4n/c points to the left. How far will the proton move before its speed reaches zero? Describe the subsequent motion in deatail/


Homework Equations



dont know whethere to about doing this with force of energy so I really don't know.


The Attempt at a Solution



Im not really sure how to start this, some helpful hints would be appretiated. Thanks.
 
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samblue said:

Homework Equations



dont know whethere to about doing this with force of energy so I really don't know.

try \vec F= \vec E q

E is electric field vector
q is the charge feeling the force
 
Ok but if I work out this force easily enough how is this going to tell me what then time is when its speed gets to zero?
 
F=ma, once you know a, and if it is constant then that's just kinematic in 1D...
 
thanks
 
Do you have any idea of what i would be expected to write in the "describe the motion" part?
 
once you know how proton moves under the field, you are done I think...
 
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