Why Can't I Solve for a2 Instead of a1 in Connected Objects Problem?

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The discussion centers on the confusion regarding solving for acceleration (a2) instead of (a1) in a connected objects problem. The user initially believes that both a1 and a2 can be expressed interchangeably, but struggles with the signs and direction of acceleration. It is clarified that maintaining consistent signs is crucial, as a positive a1 indicates acceleration towards the edge, while a positive a2 implies downward acceleration, leading to inconsistencies in their relationship. The user realizes that they incorrectly assigned a negative value to a2 from the start, which complicated their calculations. Ultimately, the key takeaway is the importance of consistent direction and polarity when solving such problems.
CVRIV
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I attached an image of the problem and solution from the book and my attempt at solving it. I don't need help solving the problem the way the book explains it; i understand that.

What I don't understand is why I can't solve for (a2) instead of (a1). The book says a2 = -a1, which makes sense to me, because the magnitudes are the same except the polarity for a2 is negative.

What about a1 = -a2? I tried solving the problem the same way except I substituted -a2 for a1 instead of the other way around and it doesn't work. I just don't understand why it wouldn't work.

Please help me understand this.
 

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You need to keep the signs consistent. In your first equation a positive a1 means the mass accelerates towards the edge. In your second equation a positive a2 means the mass accelerates downwards. That is possible - but then you have a1=a2 without the minus sign.
 
Why would positive a2 accelerate downwards? I thought positive a2 accelerates upwards?

In equation 2 I divided both sides by -1 so that I could cancel out the tension T. Was that not right?
 
Oh wow. I think I know what I did wrong. How stupid of me. :confused:
 
CVRIV said:
Why would positive a2 accelerate downwards? I thought positive a2 accelerates upwards?
It is arbitrary which direction you choose, but you have to be consistent.
 
Finally! The problem was that from the very start I was inverting the polarity of m1a2. I kept writing down T - m2g = -m2a2. I did that because I had it in my head that a2 was negative, which it is, but only after solving for a2. By assigning it as negative from the start, I was in fact just screw it all up. Also... I had it stuck in my head that I had to add the two equations together. I went back to the previous problem in the book, which as a Atwood's Machine problem, and it was subtracting the equations. I I thought I was doing it wrong so I told myself I have to subtract the problems. That's when I realized, fully realized, that it totally depended on the cancellation of T. I get it now. Thanks for your help.
 

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