Why Can't I Solve This Complex Math Equation?

  • Thread starter Thread starter aisha
  • Start date Start date
  • Tags Tags
    Complex
AI Thread Summary
The discussion revolves around solving a complex math equation involving rational expressions. The original poster struggles to find the correct solutions, which are x=3 and x=3/2. Participants suggest multiplying through by the least common denominator (LCD) and simplifying the equation to form a quadratic. After some back-and-forth, the original poster realizes they made a minor error in their calculations, leading to incorrect solutions. Ultimately, they confirm that they have successfully solved the equation after reviewing their work.
aisha
Messages
584
Reaction score
0
I tried to do this problem soo many times but can't even get close to the answer, I don't know what to do.

[(x)/(x-2)]+2=[(5x)/(x+2)]+[(3x+1)/(x^(2)-4)]

ok I know the LCD is (x+2)(x-2) and that x^(2)-4 is a perfect square that can be written as (x-2) (x+2)

But I can't get the solution it says x=3, 3/2

PLEASE HELP ME SOMEONE :confused:
 
Physics news on Phys.org
dear aisha

just make sure that the denominator is equal to x²-4 everywhere...
then you can forget about it (ofcourse x can't be 2 or -2)


like this :

[(x)(x+2)+2(x²-4)=[(5x)(x-2)+[(3x+1)]

Then solve for x...

can you go on from here ?

regards
marlon
 
If you multiply through by the LCD, you'll get:

(x/(x-2))(x-2)(x+2) + 2(x^2-4) = (5x/(x+2))(x-2)(x+2) + ((3x+1)/(x^2-4))(x+2)(x-2)

Simplifying gives you

x(x+2) + 2(x^2 - 4) = 5x(x-2) + (3x+1)

Multiply it out, collect similar terms, and you'll have a quadratic. That can be factored, or you can use the Quadratic Formula. Don't forget to distribute minus signs.

Does that help?
 
Diane_ said:
If you multiply through by the LCD, you'll get:

(x/(x-2))(x-2)(x+2) + 2(x^2-4) = (5x/(x+2))(x-2)(x+2) + ((3x+1)/(x^2-4))(x+2)(x-2)

Simplifying gives you

x(x+2) + 2(x^2 - 4) = 5x(x-2) + (3x+1)

Multiply it out, collect similar terms, and you'll have a quadratic. That can be factored, or you can use the Quadratic Formula. Don't forget to distribute minus signs.

Does that help?

YES THAT HELPS, BUT The quadratic formula I got after multiplied out and collected the like terms was -2x^(2)-x+1 and this factored out and x=-1/2 or x=-1 but the solutions were x=3, 3/2 am I wrong or is the solution wrong?
 
I think you're off somewhere. The quadratic I ended up with was

2x^2 - 9x + 9 = 0

which has the "proper" solutions. It's probably a simple math error. Go back through it and check it.

Unsolicited advice: I have found that students often make those little errors because they're trying to go too fast. I know that the grunt work of algebra can be snore-inducing, but you need to take it slowly at first. Speed comes with experience, and experience is what you're lacking right now. You'll get there, though. All it takes is time. :) </mommy-mode>
 
Thanks Diane I got it FINALLY :smile:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top