Why Does a Gyroscope's Spin Axis Maintain Its Direction?

AI Thread Summary
The spin axis of a gyroscope maintains its direction due to the conservation of angular momentum, which states that in the absence of torque, angular momentum remains constant. This principle is analogous to Newton's second law for linear momentum. The angular momentum vector, which is derived from the cross product of the radius and momentum, points in the direction of the spin axis. Consequently, without external forces acting on it, the gyroscope will continue to spin at a constant speed and direction. Thus, the spin axis remains stable unless influenced by external torques.
powerball
Messages
13
Reaction score
0
In GPB's experimental conditions, a negligible amount of precession takes place.

So in terms of rotational inertia, why does the spin axis of a gyroscopes remain pointing in the same direction?

Also, why would changes in space-time cause the axis to change?

Thanks
 
Physics news on Phys.org
Actually i understand the second part, just not the rotational inertia bit
 
why does the spin axis of a gyroscopes remain pointing in the same direction?

Because of the conservation of angular momentum. In absence of a torque the angular momentum of the gyroscope is conserved. This is basically the rotational analog of Newtons second law for conservation of 'normal momentum' in absence of a force.

The angular momentum, which is a vector, points in the direction of the spin axis, because it is the crossproduct of the radius and momentum of the gyroscope. In absence of a torque the gyroscope will spin with a constant speed AND direction. So the spin axis of the gyroscope will remain pointing in the same direction.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top