Why does a hydrogen gas tube produce a hydrogen atomic spectrum?

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Discussion Overview

The discussion centers around the phenomenon of hydrogen gas tubes producing an atomic hydrogen spectrum, despite the presence of molecular hydrogen (H2) in the tubes. Participants explore the mechanisms behind the dissociation of hydrogen molecules and the subsequent emission of atomic spectra, considering both theoretical and experimental perspectives.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that the high voltage in hydrogen gas tubes leads to the dissociation of H2 molecules into atomic hydrogen, allowing for the observation of the atomic spectrum.
  • Others note that the binding energy of H2 is 4.52 eV, while the excitation energy for the Balmer series requires at least 12 eV, indicating that the energy supplied is sufficient to break the molecules apart.
  • A participant questions whether there is a quantum mechanical justification for the likelihood of dissociation over electron excitation at higher energy levels.
  • Some argue that the continuous bombardment of molecules by energetic electrons results in rapid dissociation, leaving atomic hydrogen to emit light.
  • Concerns are raised about the rates of dissociation versus recombination of hydrogen molecules, questioning how it can be determined that dissociation occurs at a greater rate.
  • Another participant mentions that hydrogen molecules do have their own emission bands, such as Fulcher and Werner bands, and questions what influences the branching ratios between these bands and the atomic emission lines.
  • There is a discussion about the implications of continuously adding energy to the system, with some suggesting that it could lead to a plasma state where no spectrum would be observed, while others point out that emission lines are still visible.

Areas of Agreement / Disagreement

Participants express differing views on the mechanisms of dissociation and excitation in hydrogen gas tubes, with no consensus reached on the rates of dissociation versus recombination or the implications of energy input on the observed spectrum.

Contextual Notes

The discussion highlights the complexity of the processes involved in hydrogen gas tubes, including the interplay between molecular and atomic states, energy levels, and the conditions under which spectra are produced. Limitations in understanding the exact rates of dissociation and recombination are acknowledged.

amilton
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To measure the atomic hydrogen spectrum people often uses hydrogen gas tubes as light source.
Since the gas in the tube is the molecule ##H_2## , why we obtain the spectrum of atomic hydrogen?
My guess is that because the voltage is so high, so that the molecules are totally dissociated.
If you could give me some reference I would be grateful.
 
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The H2 molecule has a binding energy of 4.52 eV. Visible spectra of H, the Balmer series, requires excitation to at least ##n=3##, which requires 12 eV from the ground state. The energy required for excitation is more than enough to break apart the molecule.
 
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DrClaude said:
The H2 molecule has a binding energy of 4.52 eV. Visible spectra of H, the Balmer series, requires excitation to at least n=3, which requires 12 eV from the ground state. The energy required for excitation is more than enough to break apart the molecule.
Is there any justification based on quantum mechanics that for higher energy the process of dissociation of hydrogen molecule is more probable than that of excitation of the electron of this molecule
 
In such a tube, you are not exciting one molecule once and looking at what happens, so the branching ratios between the different outcomes are not relevant.

The molecules end up continuous being hit by energetic electrons and quickly break apart, and you are left with atoms being hit by electrons and emitting light.
 
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DrClaude said:
In such a tube, you are not exciting one molecule once and looking at what happens, so the branching ratios between the different outcomes are not relevant.

The molecules end up continuous being hit by energetic electrons and quickly break apart, and you are left with atoms being hit by electrons and emitting light.
How do we know that the rate of dissociation is greater that of recombing (production of molecules)?
 
amilton said:
How do we know that the rate of dissociation is greater that of recombing

When you start out with 100% molecules there is only one direction the system can evolve in.
 
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Vanadium 50 said:
When you start out with 100% molecules there is only one direction the system can evolve in.
Also, you keep pouring energy in the system.
 
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if you keep pouring energy to the system we will arrive to a plasma state and so no spectrum
 
Hydrogen molecules do have emission bands. Such as Fulcher bands in visible and Werner bands in vacuum UV.
What determines the branching ratio between Balmer lines and Fulcher bands in visible, or Lyman lines and Werner bands in UV?
 
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amilton said:
if you keep pouring energy to the system we will arrive to a plasma state and so no spectrum

But we do see a spectrum.

More to the point, we see emission lines, so clearly energy is leaving the system through at least that one process.
 

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