Why Does Charge Flow to Outer Spherical Shell?

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SUMMARY

The discussion clarifies why charge flows to the outer spherical shell when two concentric conducting shells are connected by a wire. The inner shell, with charge +Q, must ultimately hold no charge to eliminate the potential difference between the two shells. This is necessary to prevent an electric field from existing in the region between the shells, which would contradict the condition of zero potential difference. Therefore, the entire charge flows to the outer shell, which has a charge of +2Q.

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Highwaydude
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So there are two concentric conducting spherical shells one with radius R and another 2R with charge +Q and +2Q respectively... Now the two are connected by a conducting wire. Why does the entire charge flow to the outer shell?

Please clarify my doubts. I will be grateful.
 
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Once you connect the two spheres with the wire, current will flow until the potential difference between the spheres is zero. To achieve this, it's necessary the inner sphere hold no charge. If there were some charge left on the inner sphere after connecting it to the wire, there would be an electric field in the region between the two spheres. Upon integrating such a field in this region, we would end up with a potential difference, a contradiction with the original idea.
 
oooh, i get it... yea! thank you very much.
 

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