Why Does My Pendulum Pin Support Reaction Calculation Differ from 299N?

AI Thread Summary
The discussion centers on a calculation discrepancy regarding the support reaction force of a pendulum, which differs from the expected 299N. The user outlines their method, including calculating the mass moment of inertia, finding the center of mass, and determining angular acceleration. They apply D'Alembert's principle and Newton's laws to analyze forces acting on the pin. Ultimately, the user realizes they initially misreported the answer of 299N, confirming that their calculation method is valid and produces correct results. The conversation highlights the importance of careful verification in physics problem-solving.
cambo86
Messages
25
Reaction score
0
I've got a similar question to http://www.chegg.com/homework-help/questions-and-answers/pendulum-consists-10-kg-uniform-slender-rod-15-kg-sphere-pendulum-subjected-torque-m-50-n--q2722886 for homework. I applied the same steps I used on my homework question to this problem and I get a different answer to the 299N that they have.

Steps for my solution:
1. Calculate the mass moment of inertia around the pin.
2. Find the centre of mass of the pendulum.
3. With the total mass of the pendulum going through the centre of gravity, I calculated the angular acceleration.

\sum M = I_{0}\alpha
-M - l_{G}mg cos(45) = I_{0}\alpha

4. I calculated the normal and tangential accelerations.
a_{n} = \omega^{2}l_{G}
a_{t} = \alpha l_{G}

5. I used D'Alembert's principle (F - ma = 0) for the tangential forces and Newton (F = ma) for the normal forces. Then I can find the magnitude of forces on pin. (The dotted line arrow in the diagram above is the inertial force for D'Alembert's principle.)

I don't get the 299N stated as the answer in the original question but I can't see a problem with the steps I've gone through.
 
Last edited by a moderator:
Physics news on Phys.org
Sorry, I made a mistake in reproducing the answer of 299N. The above method works.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top