Why Does Pressure Drop in a Constricted Bronchus?

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When a person inhales, air moces down the bronchus (windpipe) at 15 cm/s. The average flow speed of the air doubles through a constriction in the bronchus. Assuming incompressible flow, determine the pressure drop in the constriction.

This confuses me as I thought if you constrict a passage (e.g artery due to cholesterol) you get a higher pressue. This question is asking for the pressure drop??

As for equation... P = F/A? not real sure at all, someone please help to get the ball rolling :)
 
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Think of water instead of air, since in the problem the fluid is given as incompressible. If the fluid is to be kept flowing without accumulating anywhere, the speed has to increase in the narrow portions. But why would the fluid rush to the constricted portions if the pressure wasn't low there compared to where it's coming from?

Use Bernoulli's law without the gravity term.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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