Why Does Using A=L^2/4 Lead to Incorrect Results in Calculating EMF in a Loop?

AI Thread Summary
Using the equation A=L^2/4 leads to incorrect results in calculating EMF because it represents the total area of the wire loop rather than the effective area within the magnetic field. The correct approach involves determining the area that contributes to the magnetic flux, which should be expressed as (L/4)*x. This distinction is crucial for accurately calculating the induced EMF. The confusion arises from misapplying the area formula, resulting in discrepancies in the final EMF calculation. Understanding the effective area in the magnetic field is essential for obtaining the correct results.
pokemon123
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Homework Statement
AP Physics C E and M 2
Relevant Equations
emf=d(flux)/dt
I am attempting to solve part b of this question. I start with the equation A=L^2/4 and I get dA=L/2(dl). Next I find dA/dt=L/2(dL/dt) and I realize dL/dt=v. Thus I get -d(flux)/dt=-BLv/2. Finally, I use emf/R=I. I get -BLv0/2R=I. However, the answer is BLv0/4R=I. I understand dA is supposed to equal L/4(dl) but I am confused why starting with the function A=L^2/4 gets me the wrong answer.
 

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pokemon123 said:
I start with the equation A=L^2/4
That's the full area of the wire loop. What you want is the area that is in the magnetic field, which will give you the flux through that loop. Think (L/4)*x.
 
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