# Why hello improper integral, how are you?

1. Feb 18, 2009

### yeahyeah<3

1. The problem statement, all variables and given/known data
integral from -1 to 1 of 3/x^2 dx

2. Relevant equations

3. The attempt at a solution
Limit
t --> infinity integral from -1 to t of 3/x^2 dx + limit t --> infinity integral from t to 1 of 3/x^2 dx

Limit
t-> infinity -3/t - (-3/-1) + Limit t--> inifinty (-3/1) - (3/t)

-3 -3 = -6

Now when I check the answer in my calc I get infinity. Thus my answer is probably wrong. Where did I go wrong?
Thanks so much =]

2. Feb 18, 2009

### D H

Staff Emeritus
Why infinity? It is (a) outside the domain, and (b) you are integrating across the singularity.

3. Feb 18, 2009

### Citan Uzuki

This should be as t→0.