Why is the Region of Convergence Important?

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The discussion focuses on the importance of the Region of Convergence (ROC) in Laplace transforms, particularly for the function f(t) = e^{(7+5j)t}u(t-1). The ROC is determined by the condition Re[s] > 7 to ensure convergence, as the exponential term dictates this requirement. The participants clarify that while the imaginary part Im[s] does not affect convergence, it is crucial to avoid conditions that make the denominator zero. They emphasize that for the function L[f(t)] = 1/(s-a), the ROC can be either Re[s] >= a or Re[s] > a, depending on the specific function. Understanding these conditions is essential for correctly applying the Laplace transform.
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One more:
after doing Laplace transform for this:

f(t) = e^{(7+5j)t}u(t-1)

where u(t) = 1 for t >= 0 and 0 otherwise;
so here's what I have:

L[f(t)] = \frac {e^{-(s-7-5j)}}{s-7-5j}

so, my reasoning was that it would converge if Re > 7 because that's the value for which exponential would converge. But why exactly do we not care about Im? I know that by Euler's formula, it e^{jw} would just be oscillating but don't I need a condition for denominator of L[f(t)]?
Thanks for your time and explanation.
 
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It is bad to have denominator of zero.
Looks like, if Re > 7 strictly (not >=)
the denominator can't be zero.
 
Thanks for reply.

lightgrav said:
It is bad to have denominator of zero. the denominator can't be zero.
yeah, i know, that's what I was asking about: do I need to state a condition for the denominator to exclude a case where it is = 0?

edit: what are the cases when Re >= or <= some value?
let's say I have L[f(t)] = \frac{1}{s-a}
so, region of convergence would be Re >= a or Re > a?

thanks again.
 
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